ABC26IN1424 · Organometallic Compounds

Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Exam: NET DEC 2015 · Marks: 2 · Difficulty: Easy

For the reaction of $\left[\mathrm{Fe}\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right)\left(\mathrm{CH}_{3}\right)(\mathrm{CO})_{2}\right]$ with $\mathrm{PMe}_{3}$, the main intermediate is
(a)$\left[\mathrm{Fe}\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right)\left(\mathrm{CH}_{3}\right)(\mathrm{CO})_{2}\left(\mathrm{PMe}_{3}\right)\right]$
(b)$\left[\mathrm{Fe}\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right)\left(\mathrm{COCH}_{3}\right)(\mathrm{CO})\right]$
(c)$\left[\mathrm{Fe}\left(\eta^{3}-\mathrm{C}_{5} \mathrm{H}_{5}\right)(\mathrm{CH}_{3})(\mathrm{CO})_{2}\right]$
(d)$\left[\mathrm{Fe}\left(\eta^{3}-\mathrm{C}_{5} \mathrm{H}_{5}\right)\left(\mathrm{COCH}_{3}\right)(\mathrm{CO})\left(\mathrm{PMe}_{3}\right)\right]$
Answer
Answer (as printed): B
Explanation
No explanation was printed for this question.

Open in whiteboard · Browse this chapter in the app