Choose the correct option for carbonyl fluoride with respect to bond angle and bond length · ABC26IN1437
Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Exam: CSIR NET DEC 2015 · Marks: 2 · Difficulty: Medium
Choose the correct option for carbonyl fluoride with respect to bond angle and bond length
(a)$\angle \mathrm{F}-\mathrm{C}-\mathrm{F}>\angle \mathrm{F}-\mathrm{C}-\mathrm{O}$ and $\mathrm{C}-\mathrm{F}>\mathrm{C}-\mathrm{O}$
(b)$\angle \mathrm{F}-\mathrm{C}-\mathrm{F}>\angle \mathrm{F}-\mathrm{C}-\mathrm{O}$ and $\mathrm{C}-\mathrm{F}<\mathrm{C}-\mathrm{O}$
(c)$\angle \mathrm{F}-\mathrm{C}-\mathrm{F}<\angle \mathrm{F}-\mathrm{C}-\mathrm{O}$ and $\mathrm{C}-\mathrm{F}>\mathrm{C}-\mathrm{O}$
(d)$\angle \mathrm{F}-\mathrm{C}-\mathrm{F}<\angle \mathrm{F}-\mathrm{C}-\mathrm{O}$ and $\mathrm{C}-\mathrm{F}<\mathrm{C}-\mathrm{O}$
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
The C=O double bond is shorter than C–F, and the doubly bonded oxygen demands more room (Bent's rule/VSEPR): ∠F–C–F (108°) < ∠F–C–O (126°).
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