Question Bank › Inorganic Chemistry › Organometallic Compounds › ABC26IN1482The hydrocarbon having an analogous structure to that of P₄ O₆ is · ABC26IN1482 Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Organometallic Compounds – General · Exam: CSIR NET DEC 2018 · Marks: 2 · Difficulty: Easy
The hydrocarbon having an analogous structure to that of $\mathrm{P}_{4} \mathrm{O}_{6}$ is
(a) $\left[(\mathrm{CH})_{4}\left(\mu-\mathrm{CH}_{2}\right)_{6}\right]$
(c) $\left[\left(\mathrm{CH}_{2}\right)_{4}(\mu-\mathrm{CH})_{6}\right]$
(b) $\left[(\mathrm{CH})_{6}\left(\mu-\mathrm{CH}_{2}\right)_{4}\right]$
(d) $\left[\left(\mathrm{CH}_{2}\right)_{4}(\mu-\mathrm{CH})_{4}\right]$
Answer Answer: A ✓ checked by 4AB · confidence high
Explanation P₄O₆ is a P₄ tetrahedron with six O atoms bridging its edges. The hydrocarbon analogue puts CH at the four corners and CH₂ across the six edges: [(CH)₄(μ-CH₂)₆] (adamantane-like).
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