The reaction of [(5-C5H5)Fe(CO)2] with CH3I gives compound A. The 1H NMR spectrum of A shows two singlets in an integrated intensity ratio of 3:5. Compound A upon interaction with PPh3 gives compound B. The 1H NMR spectrum of B shows 3 sets of signals in an integrated intensity ratio of 3:5:15. Compounds A and B respectively are

ABC26OR0134 · Organic Spectroscopy

Subject: Organic Chemistry · Chapter: Organic Spectroscopy · Topic: NMR 1H · Exam: CSIR-NET JUNE 2018 · Marks: 2 · Difficulty: Hard

The reaction of $[(\eta^{5}\text{-}\mathrm{C_5H_5})\mathrm{Fe}(\mathrm{CO})_2]$ with $\mathrm{CH_3I}$ gives compound A. The $^{1}\mathrm{H}$ NMR spectrum of A shows two singlets in an integrated intensity ratio of 3:5. Compound A upon interaction with $\mathrm{PPh_3}$ gives compound B. The $^{1}\mathrm{H}$ NMR spectrum of B shows 3 sets of signals in an integrated intensity ratio of 3:5:15. Compounds A and B respectively are

(a)