The IR stretching frequencies (cm⁻¹) for the compound X are as follows: 3300-3500 (s, br); 3000 (m); 2225… · ABC26OR0713
Subject: Organic Chemistry · Chapter: Organic Spectroscopy · Topic: Organic Spectroscopy – General · Exam: GATE 2000-2022 · Marks: 2 · Difficulty: Medium
The IR stretching frequencies ($\mathrm{cm^{-1}}$) for the compound X are as follows: $3300-3500$ (s, br); $3000$ (m); $2225$ (s); $1680$ (s). 
The correct assignment of the absorption bands is:
The correct assignment of the absorption bands is:(a)$\bar{\nu}_{\mathrm{(OH)}} = 3300-3500;\ \bar{\nu}_{\mathrm{(CH)}} = 3000;\ \bar{\nu}_{\mathrm{(CN)}} = 2225;\ \bar{\nu}_{\mathrm{(CO)}} = 1680$
(b)$\bar{\nu}_{\mathrm{(OH)}} = 3000;\ \bar{\nu}_{\mathrm{(CH)}} = 3300-3500;\ \bar{\nu}_{\mathrm{(CN)}} = 2225;\ \bar{\nu}_{\mathrm{(CO)}} = 1680$
(c)$\bar{\nu}_{\mathrm{(OH)}} = 3300-3500;\ \bar{\nu}_{\mathrm{(CH)}} = 3000;\ \bar{\nu}_{\mathrm{(CN)}} = 1680;\ \bar{\nu}_{\mathrm{(CO)}} = 2225$
(d)$\bar{\nu}_{\mathrm{(OH)}} = 3000;\ \bar{\nu}_{\mathrm{(CH)}} = 3300-3500;\ \bar{\nu}_{\mathrm{(CN)}} =;\ 1680\ \bar{\nu}_{\mathrm{(CO)}} = 2225$
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
ν(O–H) 3300–3500 (broad), ν(C–H) 3000, ν(C≡N) 2225, ν(C=O) 1680 cm⁻¹ (a).
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