The specific rotation of optically pure (R)-2-bromobutane is -112.00. A given sample of 2-bromobutne exhibited a specific rotation of -82.88. The percentage of (S)-(+)-enantiomer present in this sample is ____
Answer
Answer (as printed): 13
The options are missing from the source scan for this question, so there is nothing here for this letter to point at. The letter is what the book printed.
Explanation
Answer: 13 % — ee = 82.88/112.00 = 74 % (R), so R = 87 % and S = 13 %.