Given (i) Zn + 4NH₃ → Zn(NH₃)₄²⁺ + 2e, Eo = 1.03 V (ii) Zn → Zn⁺² + 2e, E⁰ = 0.763 V the formation constant of the complex Zn(NH₃)₄²⁺ is approximately

Given (i) Zn + 4NH₃ → Zn(NH₃)₄²⁺ + 2e, Eo = 1.03 V (ii) Zn → Zn⁺² + 2e, E⁰ = 0.763 V the formation constant… · ABC26PH0067

Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Exam: CSIR NET DEC 2016 · Marks: 2 · Difficulty: Hard

Given (i) $\mathrm{Zn + 4NH_3 \rightarrow Zn(NH_3)_4^{2+} + 2e}$,

$E^{o} = 1.03\ \mathrm{V}$

(ii) $\mathrm{Zn \rightarrow Zn^{+2} + 2e}$,

$E^{0} = 0.763\ \mathrm{V}$

the formation constant of the complex $\mathrm{Zn(NH_3)_4^{2+}}$ is approximately

(a)$1 \times 10^{5}$

(b)$1 \times 10^{7}$

(c)$1 \times 10^{9}$

(d)$1 \times 10^{12}$

Answer

Answer (as printed): C

Explanation

No explanation was printed for this question.

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