The 2 s orbital of H - atom has radial node at 2 a₀ because ψ2 s is proportional to · ABC26PH0265

Subject: Physical Chemistry · Chapter: Atomic Structure · Topic: Atomic Structure – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium

The 2 s orbital of H - atom has radial node at $2 \mathrm{a}_{0}$ because $\psi_{2 \mathrm{s}}$ is proportional to

(a)$\left(\frac{1}{2} + \frac{r}{a_0}\right)$

(b)$\left(2 + \frac{r}{a_0}\right)$

(c)$\left(2 - \frac{r}{a_0}\right)$

(d)$\left(2 - \frac{r}{2a_0}\right)$

Answer

Answer: C ✓ checked by 4AB · confidence high

Explanation

ψ₂s ∝ (2 − r/a₀)e^(−r/2a₀), which vanishes at r = 2a₀ (c).

Study loop for Atomic Structure