The de-Broglie wavelength of the electron is ( lambda )/pm= (a/() ). The value of 'a' in volts is

ABC26PH0285 · Atomic Structure

Subject: Physical Chemistry · Chapter: Atomic Structure · Topic: Atomic Structure – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium

The de-Broglie wavelength of the electron is $\frac{\lambda}{\mathrm{pm}}=\left(\frac{\mathrm{a}}{\varphi}\right)$. The value of 'a' in volts is

(a)$1.5 \times 10^{-18}$

(b)$1.5 \times 10^{6}$

(c)$6.63 \times 10^{-5}$

(d)$2.5 \times 10^{18}$

Answer

Answer (as printed): B

Explanation

No explanation was printed for this question.