The de-Broglie wavelength of the electron is (λ)/pm = (a/(φ)). The value of 'a' in volts is · ABC26PH0285

Subject: Physical Chemistry · Chapter: Atomic Structure · Topic: Atomic Structure – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium

The de-Broglie wavelength of the electron is $\frac{\lambda}{\mathrm{pm}} = \left(\frac{a}{\varphi}\right)$. The value of 'a' in volts is

(a)$1.5 \times 10^{-18}$

(b)$1.5 \times 10^{6}$

(c)$6.63 \times 10^{-5}$

(d)$2.5 \times 10^{18}$

Answer

Answer (as printed): B

Explanation

No explanation was printed for this question.

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