In a molecule XY, let $\psi_X$ and $\psi_Y$ denote normalized atomic orbitals of atoms X and Y, respectively. A normalized molecular orbital of XY is given by $\psi_+ = 0.56(\psi_X + \psi_Y)$. The value of the overlap integral of $\psi_X$ and $\psi_Y$ is ____ (Upto two decimal place)
Answer
SELF-PRACTICE — the source book printed no answer.
Nothing is invented here, so this question has no answer on record.
Explanation
Answer: 0.59 — 0.56²(2 + 2S) = 1 gives 2 + 2S = 3.189, so S = 0.59.