ABC26PH0343 · Concentration B B

Subject: Physical Chemistry · Chapter: Concentration B B · Topic: Concentration B B – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium

The rate constant of two reactions as temperature T are $\mathrm{k}_{1}(\mathrm{T})$ and $\mathrm{k}_{2}(\mathrm{T})$ and the corresponding activation energies are $\mathrm{E}_{1}$ and $\mathrm{E}_{2}$ with $\mathrm{E}_{2}>\mathrm{E}_{1}$. When temperature is raised from $\mathrm{T}_{1}$ and $\mathrm{T}_{2}$, which one of the following relations is correct?
(a)$\frac{\mathrm{k}_{1}\left(\mathrm{T}_{2}\right)}{\mathrm{k}_{1}\left(\mathrm{T}_{1}\right)}=\frac{\mathrm{k}_{2}\left(\mathrm{T}_{2}\right)}{\mathrm{k}_{2}\left(\mathrm{T}_{1}\right)}$
(b)$\frac{\mathrm{k}_{1}\left(\mathrm{T}_{2}\right)}{\mathrm{k}_{1}\left(\mathrm{T}_{1}\right)}>\frac{\mathrm{k}_{2}\left(\mathrm{T}_{2}\right)}{\mathrm{k}_{2}\left(\mathrm{T}_{1}\right)}$
(c)$\frac{\mathrm{k}_{1}\left(\mathrm{T}_{2}\right)}{\mathrm{k}_{1}\left(\mathrm{T}_{1}\right)} \geq \frac{\mathrm{k}_{2}\left(\mathrm{T}_{2}\right)}{\mathrm{k}_{2}\left(\mathrm{T}_{1}\right)}$
(d)$\frac{\mathrm{k}_{1}\left(\mathrm{T}_{2}\right)}{\mathrm{k}_{1}\left(\mathrm{T}_{1}\right)}<\frac{\mathrm{k}_{2}\left(\mathrm{T}_{2}\right)}{\mathrm{k}_{2}\left(\mathrm{T}_{1}\right)}$
Answer
Answer (as printed): D
Explanation
No explanation was printed for this question.

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