The equilibrium constant for the reaction (a) NO(g) ⇌ N₂O(g)+NO₂(g) at 25°C is closest to: [Δ Go=-104.18 kJ… · ABC26PH0444

Subject: Physical Chemistry · Chapter: Chemical Equilibrium · Topic: Equilibria – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Easy

The equilibrium constant for the reaction

(a) $\mathrm{NO(g) \rightleftharpoons N_2O(g)+NO_2(g)}$

at 25°C is closest to: $\left[\Delta \mathrm{G}^{\mathrm{o}}=-104.18\,\mathrm{kJ}; \mathrm{R}=8.314\,\mathrm{J\,mol^{-1}\,K^{-1}}\right]$

(a)$1.8 \times 10^{18}$

(b)1.651

(c)1.043

(d)$5.7 \times 10^{-19}$

Answer

Answer: A ✓ checked by 4AB · confidence high

Explanation

K = exp(−ΔG°/RT) = exp(104180/(8.314 × 298)) = e^42.05 ≈ 1.8 × 10¹⁸ (a).

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