The frequency (in $\mathrm{cm}^{-1}$, rounded off to two decimal places) for pure rotational line in the spectrum of NO molecule due to change in the quantum number from $\mathrm{J}=1$ to $\mathrm{J}=2$ is ____ (Given: Moment of inertia of $\mathrm{NO}=1.6427 \times 10^{-46} \mathrm{kg} \mathrm{m}^{2} ; \mathrm{h}=6.626 \times 10^{-34} \mathrm{J} \mathrm{s} ; \mathrm{c}=3 \times 10^{8} \mathrm{m} / \mathrm{s}$ )
Answer
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