ABC26PH0608 · Thermodynamics

Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Free Energy Equilibria · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium

The standard Gibbs free energy change of the reaction shown below is $-2.7 \mathrm{kJ} \mathrm{mol}^{-1}$.
\[ \mathrm{Sn}(\mathrm{s})+\mathrm{Pb}^{2+}=\mathrm{Sn}^{2+}+\mathrm{Pb}(\mathrm{s}) \]
Given that $\mathrm{E}^{0}\left(\mathrm{Pb}^{2+} / \mathrm{Pb}\right)$ is -0.126 V , the value of $\mathrm{E}^{0}\left(\mathrm{Sn}^{2+} / \mathrm{Sn}\right)$ in V is ____ (up to two decimal places)
Answer
SELF-PRACTICE — the source book printed no answer.

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Explanation
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