1 10-6 moles of the enzyme carbonic anhyrase dehydrates H2 CO3 to produce 0.6 mol of CO2 per second. The turnover number of the enzyme is:

ABC26PH0681 · Chemical Kinetics

Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Enzyme Kinetics · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Medium

$1 \times 10^{-6}$ moles of the enzyme carbonic anhyrase dehydrates $\mathrm{H}_{2} \mathrm{CO}_{3}$ to produce 0.6 mol of $\mathrm{CO}_{2}$ per second. The turnover number of the enzyme is:

(a)$\mathrm{N}_{\mathrm{A}} \times 6 \times 10^{-5}$

(b)$(1/6) \times 10^{-5}$

(d)$6 \times 10^{5}$

(c)$(6 \times 10^{5}) / \mathrm{N_A}$

Answer

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