1 × 10⁻⁶ moles of the enzyme carbonic anhyrase dehydrates H₂ CO₃ to produce 0.6 mol of CO₂ per second. The… · ABC26PH0681

Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Enzyme Kinetics · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Medium

$1 \times 10^{-6}$ moles of the enzyme carbonic anhyrase dehydrates $\mathrm{H}_{2} \mathrm{CO}_{3}$ to produce 0.6 mol of $\mathrm{CO}_{2}$ per second. The turnover number of the enzyme is:

(a)$\mathrm{N}_{\mathrm{A}} \times 6 \times 10^{-5}$

(b)$(1/6) \times 10^{-5}$

(d)$6 \times 10^{5}$

(c)$(6 \times 10^{5}) / \mathrm{N_A}$

Answer

Answer: D ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Explanation

Turnover number = moles of product per mole of enzyme per second = 0.6/(1×10⁻⁶) = 6×10⁵ s⁻¹.

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