For a reaction with rate equation -dC/dt = kC², C₀ and C are the concentrations of the reactant at time 0 and… · ABC26PH0683
Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Medium
For a reaction with rate equation $-dC/dt = kC^2$, $C_0$ and C are the concentrations of the reactant at time 0 and t respectively. If 10 minutes were required for $C_0$ to become $C_0/2$, the time required for $C_0$ to become $C_0/4$ is:
(a)10 min
(b)20 min
(c)30 min
(d)40 min
Answer
Answer: C ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
Second order: t for C₀ → C₀/4 is 3/(kC₀) = 3 × t₁/₂ = 30 min (each successive halving takes twice as long: 10 + 20).