At 25°C, the solubility product (Ksp) of CaF₂ in water is 3.2 × 10⁻¹¹. The solubility (in mole per kg of water) of the salt at the same temperature (ignore ion pairing) is

At 25°C, the solubility product (Ksp) of CaF₂ in water is 3.2 × 10⁻¹¹. The solubility (in mole per kg of… · ABC26PH0745

Subject: Physical Chemistry · Chapter: Ionic Equilibrium · Topic: Ionic Equilibrium – General · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Medium

At 25°C, the solubility product $(K_{sp})$ of $\mathrm{CaF_2}$ in water is $3.2 \times 10^{-11}$. The solubility (in mole per kg of water) of the salt at the same temperature (ignore ion pairing) is

(a)$4.0 \times 10^{-6}$

(b)$3.2 \times 10^{-4}$

(c)$2.5 \times 10^{-4}$

(d)$2.0 \times 10^{-4}$

Answer

Answer (as printed): D

Explanation

No explanation was printed for this question.

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