For H₂ molecule, the fundamental vibrational frequency (νe) in wavenumbers can be taken as 4400 cm⁻¹. The… · ABC26PH0766

Subject: Physical Chemistry · Chapter: Physical Spectroscopy · Topic: Physical Spectroscopy – General · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Medium

For $\mathrm{H_2}$ molecule, the fundamental vibrational frequency ($\bar{\nu}_e$) in wavenumbers can be taken as $4400\ \mathrm{cm^{-1}}$. The zero-point energy of the molecule is ____ $\mathrm{kJ\,mol^{-1}}$ (rounded up to two decimal places).
$$[h = 6.6 \times 10^{-34}\ \mathrm{J\,s},\ c = 3 \times 10^{8}\ \mathrm{m\,s^{-1}},\ N_A = 6 \times 10^{23}\ \mathrm{mol^{-1}}]$$
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