The maximum of a function Ae-ax² (A > 0; a > 0) is at x = · ABC26PH0788

Subject: Physical Chemistry · Chapter: Quantum Chemistry · Topic: Quantum Chemistry – General · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Easy

The maximum of a function $Ae^{-ax^2}$ ($A > 0$; $a > 0$) is at $x =$

(a)0

(b)$+\infty$

(c)$-\infty$

(d)$1/\sqrt{a}$

Answer

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Explanation

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