ABC26PH0807 · Solid State Chemistry

Subject: Physical Chemistry · Chapter: Solid State Chemistry · Topic: Solid State – General · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Medium

The ratio of the nearest neighbour atomic distances in body-centered cubic (bcc) and face-centered cubic (fcc) crystals with the same unit cell edge length is

(a)$\sqrt{\frac{3}{2}}$

(b)$\frac{\sqrt{3}}{2}$

(c)$\frac{1}{\sqrt{2}}$

(d)$\frac{1}{2}$

Answer

Answer (as printed): C

Explanation

No explanation was printed for this question.

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