A system undergoes two cyclic processes 1 and 2. Process 1 is reversible and process 2 is irreversible. The… · ABC26PH0828
Subject: Physical Chemistry · Chapter: Thermodynamics · Topic: Thermodynamics – General · Exam: JAM 2001-2022 · Marks: 2 · Difficulty: Medium
A system undergoes two cyclic processes 1 and 2. Process 1 is reversible and process 2 is irreversible. The correct statement relating to the two processes is
(a)$\Delta S$ (for process 1) = 0, while $\Delta S$ (for process 2) $\neq 0$
(b)$q_{cycle} = 0$ for process 1 and $q_{cycle} \neq 0$ for process 2
(c)More heat can be converted to work in process 1 than in process 2
(d)More work can be converted to heat in process 1 than in process 2
Answer
Answer: C ✓ checked by 4AB · confidence high
The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
ΔS of the system is zero for any cycle (state function), and q_cycle = −w_cycle ≠ 0 in both; the difference is that the reversible cycle converts the maximum heat into work.