ABC26PH0881 · Chemical Kinetics

Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Rate Laws Order · Exam: NET JUNE 2011 · Marks: 2 · Difficulty: Medium

The half-life of a zero order reaction $(\mathrm{A} \rightarrow \mathrm{P})$ is given by ( $\mathrm{k}=$ rate constant ):
(a)$\mathrm{t}_{1 / 2}=\frac{[\mathrm{A}]_{0}}{2 \mathrm{k}}$
(b)$\mathrm{t}_{1 / 2}=\frac{2.303}{\mathrm{k}}$
(c)$\mathrm{t}_{1 / 2}=\frac{\left[\mathrm{A}_{0}\right]}{\mathrm{k}}$
(d)$\mathrm{t}_{1 / 2}=\frac{1}{\mathrm{k}\left[\mathrm{A}_{0}\right]}$
Answer
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Explanation
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