The decomposition of NH₃ on Mo surface follows Langmuir-Hinshelwood mechanism. The decomposition was carried… · ABC26PH0895
Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Rate Laws Order · Exam: CSIR NET DEC 2012 · Marks: 2 · Difficulty: Hard
The decomposition of $\mathrm{NH_3}$ on Mo surface follows Langmuir-Hinshelwood mechanism. The decomposition was carried out at low pressures. The initial pressure of $\mathrm{NH_3}$ was $10^{-2}$ torr. The pressure of $\mathrm{NH_3}$ was reduced to $10^{-4}$ torr in 10 minutes. The rate constant of decomposition of $\mathrm{NH_3}$ is:
(a)$9.9 \times 10^{-4}\ \mathrm{torr\,min^{-1}}$
(b)$0.4606\ \mathrm{min^{-1}}$
(c)$9.9 \times 10^{-3}\ \mathrm{torr\,min^{-1}}$
(d)$0.693\ \mathrm{min^{-1}}$
Answer
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