Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Enzyme Kinetics · Exam: NET DEC 2015 · Marks: 2 · Difficulty: Medium
$v_{\max }$ and $\mathrm{K}_{\mathrm{m}}$ for an enzyme catalyzed reaction are $2.0 \times 10^{-3} \mathrm{Ms}^{-1}$ and $1.0 \times 10^{-6} \mathrm{M}$, respectively. The rate of the reaction when the substrate concentration is $1.0 \times 10^{-6} \mathrm{M}$ is
(a)$3.0 \times 10^{-3} \mathrm{s}^{-1}$
(b)$1.0 \times 10^{-3} \mathrm{s}^{-1}$
(c)$2.0 \times 10^{-3} \mathrm{s}^{-1}$
(d)$0.5 \mathrm{s}^{-1}$
Answer
SELF-PRACTICE — the source book printed no answer.
Nothing is invented here, so this question has no answer on record.