The reaction rate of a self-catalyzed polyesterification reaction is given as -(d[COOH])/dt=k[COOH]2[OH] If [M] is the initial concentration of hydroxyl and carboxyl monomers, then the degree of polymerization, is given by

ABC26PH1196 · Polymer Chemistry

Subject: Physical Chemistry · Chapter: Polymer Chemistry · Topic: Polymerisation Kinetics · Exam: NET JUNE 2019 · Marks: 2 · Difficulty: Medium

The reaction rate of a self-catalyzed polyesterification reaction is given as

\[ -\frac{\mathrm{d}[\mathrm{COOH}]}{\mathrm{dt}}=\mathrm{k}[\mathrm{COOH}]^{2}[\mathrm{OH}] \]

If [M] is the initial concentration of hydroxyl and carboxyl monomers, then the degree of polymerization, <N> is given by

(a)$\langle\mathrm{N}\rangle=2[\mathrm{M}]_{0}^{2} \mathrm{kt}$

(b)$\langle\mathrm{N}\rangle^{2}=2[\mathrm{M}]_{0}^{2} \mathrm{kt}$

(c)$\langle\mathrm{N}\rangle^{2}=2[\mathrm{M}]_{0}^{2} \mathrm{kt}+1$

(d)$\langle\mathrm{N}\rangle^{2}=2[\mathrm{M}]_{0} \mathrm{kt}+1$

Answer

SELF-PRACTICE — the source book printed no answer.

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Explanation

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