For a linear molecule the mean energies for translation, rotation (T ) and vibration (T ) follow ratio:

ABC26PH1405 · Statistical Thermodynamics

Subject: Physical Chemistry · Chapter: Statistical Thermodynamics · Topic: Statistical Thermodynamics – General · Exam: NET JUNE 2019 · Marks: 2 · Difficulty: Medium

For a linear molecule the mean energies for translation, rotation $\left(\mathrm{T} \gg \theta_{\mathrm{r}}\right)$ and vibration $\left(\mathrm{T} \gg \theta_{\mathrm{v}}\right)$ follow ratio:

(a)$1: \frac{3}{2}: 1$

(b)$\frac{3}{2}: 1: 1$

(c)$1: \frac{1}{2}: 1$

(d)$\frac{1}{2}: 1: 1$

Answer

Answer (as printed): B

Explanation

No explanation was printed for this question.

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