Quantum Chemistry

ABC26PH1167 · The total pi -electron density on the four carbon atoms of trans butadiene are in the ratio · 2020-2021 self-practice

ABC26PH1168 · Consider an electron me=9.1 × 10-31 kg having energy 13.6 eV, confined in an infinite potential well. If the potential energy inside the… · 2020-2021 self-practice

ABC26PH1169 · When a hydrogen atom is exposed to a perturbation V=E. z, the first order correction to the wave function comes only from the orbital · 2020-2021 self-practice

ABC26PH0141 · The trial wave function of a system is expanded as psi t=c1 phi 1+c2 phi 2. The matrix elements of the Hamiltonian are phi 1 | H | phi 1… · 2012

ABC26PH1227 · The trial wave function of a system is expanded as psi t=c1 phi 1+c2 phi 2. The matrix elements of the Hamiltonian are phi 1 H phi 1=0; phi… · DEC 2012 self-practice

ABC26PH0160 · For some one-electron system with l=0 and m=0, the functions N0 e- sigma and N1(2- sigma)e- sigma refer respectively to the ground (E0) and… · 2014

ABC26PH1262 · For some one-electron system with l=0 and m=0, the functions N0 e- sigma and N1(2- sigma) e- sigma refer respectively to the ground (E0)… · JUNE 2014 self-practice

ABC26PH1279 · Choosing some Hamiltonian H and an orthonormal basis, a linear variation is carried out to get approximately energies Ej With 2 basis… · JUNE 2016 self-practice

ABC26PH1294 · Given a trial wave function psi =C1 phi 1+C2 phi 2 and the Hamiltonian matrix elements. ∫ phi 1* H phi 1 dv=0, ∫ phi 1* H phi 2 dv=2.5, ∫… · JUNE 2016 self-practice

ABC26PH1312 · The energy functional from a trial wave function is E(alpha)= (alpha 3-3 alpha) / 6. The variationally optimized energy is · JUNE 2016 self-practice

ABC26PH0178 · In linear variation method using two orthogonal basis functions, the two roots obtained are epsilon 0 and epsilon 1 (epsilon 0< epsilon 1)… · 2019