The correct statement about base hydrolysis of $[\mathrm{Co(py)_4Cl_2}]^{+}$ (py-pyridine) is
(a)rate expression is, Rate-$\mathrm{k}[\mathrm{Co(py)_4Cl_2}]^{+}[\mathrm{OH^{-}}]$
(b)reaction does not depend on hydroxide ion concentration
(c)reaction proceeds through $\mathrm{S_{N1}CB}$ mechanism
(d)intermediate involved in this reaction is $[\mathrm{Co(py)_4Cl_2(OH)}]$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Pyridine has no N–H, so no conjugate base can form and the S_N1CB pathway is closed; base hydrolysis of [Co(py)₄Cl₂]⁺ is therefore slow and independent of [OH⁻] — statement (2).