The correct match for column A with column B is: · ABC26IN0176

Subject: Inorganic Chemistry · Chapter: Lanthanides and Actinides · Topic: Lanthanides & Actinides – General · Exam: CSIR NET 2020 · Marks: 2 · Difficulty: Medium

The correct match for column A with column B is:
Column AColumn B
(a) $\mathrm{f}\nrightarrow\mathrm{f}$ transition(i) $\mathrm{Tb^{3+}}$
(b) ${}^{5}\mathrm{D}_{0}\rightarrow{}^{7}\mathrm{F}_{n}$ emission(ii) $\mathrm{Lu^{3+}}$
(c) ${}^{5}\mathrm{D}_{4}\rightarrow{}^{7}\mathrm{F}_{n}$ emission(iii) $\mathrm{Sm^{3+}}$
(d) Overlapping $J$ levels(iv) $\mathrm{Eu^{3+}}$
(a)(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
(b)(a)-(ii), (b)-(iv), (c)-(iii), (d)-(i)
(c)(a)-(ii), (b)-(iv), (c)-(i), (d)-(iii)
(d)(a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)
Answer
Answer: C ✓ checked by 4AB · confidence high

The source book printed no answer; this one was worked out and checked — see the explanation.

Explanation
Lu³⁺ (f¹⁴) has no f→f transition — (a)-(ii). ⁵D₀→⁷F_J emission is Eu³⁺ — (b)-(iv). ⁵D₄→⁷F_J emission is Tb³⁺ — (c)-(i). Closely spaced J levels of the ⁶H ground term belong to Sm³⁺ — (d)-(iii). This is option (c).

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