Consider the following reaction : N₃P₃Cl₆ + 6HNMe₂ → [A]N₃P₃Cl₃(NMe₂)₃ + 3 Me₂NH · HCl The number of possible… · ABC26IN0199

Subject: Inorganic Chemistry · Chapter: Main Group Elements · Topic: Main Group Elements – General · Exam: CSIR NET 2015 · Marks: 2 · Difficulty: Hard

Consider the following reaction :

$\mathrm{N_3P_3Cl_6 + 6HNMe_2 \rightarrow \underset{[A]}{N_3P_3Cl_3(NMe_2)_3} + 3\,Me_2NH \cdot HCl}$

The number of possible isomers for [A] is

(a)4

(b)3

(c)2

(d)5

Answer

Answer (as printed): B

Explanation

No explanation was printed for this question.

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