The source book printed no answer; this one was worked out and checked — see the explanation.
Explanation
More π back-donation lengthens C–O. Back-donation grows with negative charge on the metal: [V(CO)₆]⁻ > Cr(CO)₆ > [Mn(CO)₆]⁺; H₃B·CO has no back-donation at all and the shortest C–O. Option 2.