The compound with planr geometry is · ABC26IN0323

Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: VSEPR Geometry · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Easy

The compound with planr geometry is

(a)$\mathrm{N}(\mathrm{t}-\mathrm{Bu})_{3}$

(b)$\mathrm{NPh}_{3}$

(c)$\mathrm{NF}_{3}$

(d)$\mathrm{N}\left(\mathrm{SiH}_{3}\right)_{3}$

Answer

Answer: D ✓ checked by 4AB · confidence high

Explanation

N(SiH₃)₃ is planar because N lone-pair delocalisation into Si (σ*/d) orbitals (d).

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