The crystal field stabilization energy (CFSE) value for $\left[\mathrm{jTi}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ that has an absorption maximum at 492 nm is:
(a)$20,325 \mathrm{cm}^{-1}$
(b)$12,195 \mathrm{cm}^{-1}$
(c)$10,162 \mathrm{cm}^{-1}$
(d)$8,130 \mathrm{cm}^{-1}$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
Δo = 10⁷/492 cm⁻¹ = 20,325 cm⁻¹. For d¹ Ti³⁺ (t₂g¹), CFSE = −0.4Δo = −0.4 × 20,325 = −8,130 cm⁻¹, i.e. a stabilisation of 8,130 cm⁻¹ (d).