The major product of the following reaction is2. HCl, $\mathrm{H_2O}$
(a)
(b)
(c)
(d)
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
Me₂SO₄/NaOH methylates every hydroxyl including the anomeric one; dilute HCl then hydrolyses only the acid-labile glycosidic OMe, giving 2,3,4,6-tetra-O-methyl glucose with a free anomeric OH (c).