Identify the product from the following reaction Product · ABC26OR0681

Subject: Organic Chemistry · Chapter: Reagents, Reaction Mechanisms & Named Reactions · Topic: Reagents, Reaction Mechanisms & Named Reactions – General · Exam: GATE 2000-2022 · Marks: 2 · Difficulty: Easy

Identify the product from the following reaction Question structure 1 of 2, ABC26OR0681 Question structure 2 of 2, ABC26OR0681 Product
(a)Option (a) structure, ABC26OR0681
(b)Option (b) structure, ABC26OR0681
(c)Option (c) structure, ABC26OR0681
(d)Option (d) structure, ABC26OR0681
Answer
Answer: A ✓ checked by 4AB · confidence high

The source book printed B; on checking, A is correct — see the explanation.

9-BBN hydroboration–oxidation is a syn addition. The new H (on the C–Me carbon) and OH (on the CH carbon) are cis, so Me and OH on adjacent carbons end up trans. Only (a) has trans (diequatorial) Me/OH. In (b) OH is axial on the carbon next to the equatorial Me, which is cis. (c) is cis and (d) is the Markovnikov tertiary alcohol. The printed key was A.

Explanation
9-BBN adds syn and anti-Markovnikov to the trisubstituted alkene. Boron goes to the less substituted CH carbon and H goes to the methyl-bearing carbon, both from the same face. H₂O₂/NaOH replaces B by OH with retention. So the new H and OH are cis, which makes CH₃ and OH on adjacent carbons trans. Only (a) has trans (diequatorial) CH₃ and OH. (b) and (c) are cis isomers, and (d) is the Markovnikov tertiary alcohol. Answer: (a).

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