Identify the correct stereochemical relationship amongst the hydrogen atoms $\mathrm{H}_{\mathrm{a}}, \mathrm{H}_{\mathrm{b}}$ and $\mathrm{H}_{\mathrm{c}}$ in the following molecule:
(a)$\mathrm{H}_{\mathrm{a}}$ and $\mathrm{H}_{\mathrm{b}}$ : enantiotopic
(b)$\mathrm{H}_{\mathrm{a}}$ and $\mathrm{H}_{\mathrm{b}}$ : diastereotopic
(c)$\mathrm{H}_{\mathrm{a}}$ and $\mathrm{H}_{\mathrm{c}}$ : enantiotopic
(d)$\mathrm{H}_{\mathrm{b}}$ and $\mathrm{H}_{\mathrm{c}}$ : diastereotopic
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Ha and Hb are the exo and endo hydrogens of the same CH₂ of norbornane; replacing one or the other gives diastereomers, so they are diastereotopic (b).