DNA Ba(OH)₂ (P) ↓ MgO/Δ PO₄³⁻ + (Q) HCl (R) + (S) + sugar In the scheme shown above (P), (Q), (R) and (S) are · ABC26OR0792

Subject: Organic Chemistry · Chapter: Natural Products · Topic: Natural Products & – General · Exam: JAM 2005-2022 · Marks: 2 · Difficulty: Medium

\[ \begin{array}{l} \mathrm{DNA} \xrightarrow{\mathrm{Ba(OH)_2}} (\mathrm{P}) \\ \Big\downarrow \mathrm{MgO}/\Delta \\ \mathrm{PO_4^{3-}} + (\mathrm{Q}) \xrightarrow{\mathrm{HCl}} (\mathrm{R}) + (\mathrm{S}) + \text{sugar} \end{array} \]
In the scheme shown above (P), (Q), (R) and (S) are
(a)(P) = purine bases, (Q) = pyrimidine bases, (R) = nucleotides, (S) = nucleosides
(b)(P) = nucleosides, (Q) = nucleotides, (R) = pyrimidine bases, (S) = purine bases
(c)(P) = nucleosides, (Q) = nucleotides, (R) = (S) = purine bases
(d)(P) = nucleotides, (Q) = nucleosides, (R) = pyrimidine base, (S) = purine base
Answer
Answer: D ✓ checked by 4AB · confidence medium
Explanation
Ba(OH)₂ breaks DNA down to nucleotides; MgO/heat removes phosphate, leaving nucleosides; HCl then cleaves the glycosidic bonds to the pyrimidine and purine bases and the sugar (d).

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