In the following reaction of (D)-Glucose, a product P is formed. (D)-Glucose [2. H₂O₂, Fe₂(SO₄)₃]1. Br₂/H₂O P… · ABC26OR0823

Subject: Organic Chemistry · Chapter: Natural Products · Topic: Natural Products & – General · Exam: JAM 2005-2022 · Marks: 2 · Difficulty: Easy

In the following reaction of (D)-Glucose, a product P is formed. $(\mathrm{D})\text{-Glucose} \xrightarrow[2.\ \mathrm{H_2O_2, Fe_2(SO_4)_3}]{1.\ \mathrm{Br_2/H_2O}} \mathrm{P}$ Among the following compounds, the one which will give the same product (P) under identical reaction conditions is
(a)Option (a) structure, ABC26OR0823
(b)Option (b) structure, ABC26OR0823
(c)Option (c) structure, ABC26OR0823
(d)Option (d) structure, ABC26OR0823
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
Br₂/H₂O then H₂O₂/Fe(III) is the Ruff degradation, which removes C-1 and gives D-arabinose from D-glucose; the C-2 epimer D-mannose (b) loses the same carbon and gives the identical product.

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