Two trial wavefunction $\phi=c_1x(a-x)$ and $\phi_2=c_1x(a-x)+c_2x^2(a-x)^2$ give ground state energies $E_1$ and $E_2$, respectively, for the microscopic particle in a 1-D box by using the variation method. If the exact ground state energy is $E_0$, the correct relationship between $E_0$, $E_1$ and $E_2$ is:
(a)$E_0=E_1=E_2$
(b)$E_0<E_1<E_2$
(c)$E_0<E_2<E_1$
(d)$E_0>E_2=E_1$
Answer
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