In the reversible chamical reaction taking place under standard condition at 298 K and 1 atm in a Daniel cell, $\mathrm{Zn}\left|\mathrm{Zn}^{2+}(\mathrm{aq})\right|\left|\mathrm{Cu}^{2+}(\mathrm{aq})\right| \mathrm{Cu}$ the heat change is
(a)equal to $\Delta \mathrm{H}^{\mathrm{o}}$
(b)equal to $\mathrm{T} \Delta \mathrm{S}^{\circ}$
(c)equal to zero
(d)equal to $\Delta \mathrm{U}^{\mathrm{o}}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
For a reversible process q_rev = TΔS°, so the heat change of the reversible Daniell cell is TΔS° (b).