A gaseous sample on exposure to total radiant energy of 6.626 J at 300 nm results in the photodissociation of 10⁻³ mol of this sample. Assuming the sample absorbs all the light, the quantum yield for this photochemical reaction is:

A gaseous sample on exposure to total radiant energy of 6.626 J at 300 nm results in the photodissociation of… · ABC26PH0470

Subject: Physical Chemistry · Chapter: Chemical Kinetics · Topic: Chemical Kinetics – General · Exam: GATE 2005-2021 · Marks: 2 · Difficulty: Medium

A gaseous sample on exposure to total radiant energy of 6.626 J at 300 nm results in the photodissociation of $10^{-3} \mathrm{mol}$ of this sample. Assuming the sample absorbs all the light, the quantum yield for this photochemical reaction is:

(a)6.023

(b)0.602

(c)60.230

(d)0.060

Answer

Answer: C ✓ checked by 4AB · confidence high

The source book printed B; on checking, C is correct — see the explanation.

Book printed (b).

Explanation

E(photon) = hc/λ = 6.626×10⁻¹⁹ J → 10¹⁹ photons = 1.66×10⁻⁵ einstein; Φ = 10⁻³/1.66×10⁻⁵ ≈ 60.2 (c).

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