$\Delta S^{0}_{\text{univ}}$ for the following reaction, at 298 K is: $\mathrm{N_2 + 3H_2 \rightarrow 2NH_3}$ $\Delta S^{0}_{\text{sys}} = -197\ \mathrm{J\,K^{-1}}$, $\Delta H^{0}_{\text{sys}} = -91.8\ \mathrm{kJ}$
(a)$-197\ \mathrm{J\,K^{-1}}$
(b)$0\ \mathrm{J\,K^{-1}}$
(c)$-308\ \mathrm{J\,K^{-1}}$
(d)$111\ \mathrm{J\,K^{-1}}$
Answer
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