Q3 · CSIR NET Chemistry, December 2012
Paper: CSIR NET December 2012 · Subject: Inorganic Chemistry · Chapter: Chemical Bonding · Topic: Chemical Bonding – General · Marks: 2 · Difficulty: Easy
Which ones among $\mathrm{CO}_{3}^{-2}$, $\mathrm{SO}_{3}$, $\mathrm{XeO}_{3}$, and $\mathrm{NO}_{3}^{-1}$, have planar structure?
(a)$\mathrm{CO}_{3}^{-2}$, $\mathrm{SO}_{3}$, and $\mathrm{XeO}_{3}$
(b)$\mathrm{SO}_{3}$, $\mathrm{XeO}_{3}$, and $\mathrm{NO}_{3}^{-}$
(c)$\mathrm{CO}_{3}^{-2}$, $\mathrm{XeO}_{3}$, and $\mathrm{NO}_{3}^{-}$
(d)$\mathrm{CO}_{3}^{-2}$, $\mathrm{SO}_{3}$, and $\mathrm{NO}_{3}^{-}$
Answer
Answer (as printed): D
Explanation
- CO3 2 : sp²-hybridization (Trigonal planar) SO3 : sp²-hybridization (Trigonal planar) XeO3 :sp-hybridization. (Trigonal pyramidal) NO3 :sp²-hybridization (Trigonal planar) - - CO3 2,SO3, and NO3 2, have planar structure.
Explanation as extracted from the printed page; notation may be imperfect.
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