Q37 · CSIR NET Chemistry, December 2012
Paper: CSIR NET December 2012 · Subject: Inorganic Chemistry · Chapter: Acids and Bases · Topic: Acids & Bases – General · Marks: 2 · Difficulty: Medium
Match each item from the List-I (compound in solvent) with that from the List-II (its behaviour) and select the correct combination using the codes given below.
| List-I | List-II |
|---|---|
| A. $\mathrm{CH_3COOH}$ in pyridine | (i) strong acid |
| B. $\mathrm{CH_3COOH}$ in $\mathrm{H_2SO}$ | (ii) weak acid |
| C. $\mathrm{HClO_4}$ in $\mathrm{H_2SO_4}$ | (iii) strong base |
| D. $\mathrm{SbF_5}$ in HF | (iv) weak base |
(a)(A-i), (B-ii), (C-iii), (D-iv)
(b)(A-ii), (B-i), (C-in), (D-iv)
(d)(A-iv), (B-ii), (C-iii), (D-i)
(c)(A-iii), (B-iv), (C-ii), (D-i)
Answer
Answer: C ✓ checked by 4AB · confidence medium
The source book printed A; on checking, C is correct — see the explanation.
Explanation
In pyridine acetic acid is fully ionised (levelled, strong acid); in H₂SO₄ it is protonated and acts as a weak base (iv); HClO₄ in H₂SO₄ is only a weak acid (ii); SbF₅ in HF forms the superacid H₂F⁺SbF₆⁻ (strong acid, i). Option (c) carries the B, C and D matches.
Study loop for Acids and Bases