Q68 · CSIR NET Chemistry, December 2012
Paper: CSIR NET December 2012 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Cluster Compounds Wade Rules · Marks: 2 · Difficulty: Medium
Consider the catalyst in column-I and reaction in column-II
4 The best match of a catalyst of column-I with the reaction nuclear column-II is
| Column-I | Column-II | ||
|---|---|---|---|
| A | $[(\mathrm{R})$-BINAP $] \mathrm{Ru}^{-2}$ | i. | Hydroformylation |
| B | $\left[\mathrm{Rh}(\mathrm{CO})_{2} \mathrm{I}_{2}\right]^{-}$ | ii. | asymmetric hydrogenation |
| C | $\left[\operatorname{Pd}\left(\mathrm{PPh}_{3}\right)_{4}\right]$ | iii. | Asymmetric hydrogen transfer |
(a)(A-ii), (B-i), (C-iv), (D-iii)
(b)(A-i), (B-ii), (C-iii), (D-iv)
(c)(A-iii), (B-i), (C-iv), (D-ii)
(d)(A-iv), (B-iii), (C-ii), (D-i)
Answer
Answer: A ✓ checked by 4AB · confidence medium
The source book printed B; on checking, A is correct — see the explanation.
Explanation
(R)-BINAP-Ru does asymmetric hydrogenation, [Rh(CO)₂I₂]⁻ carbonylation/hydroformylation-type chemistry, and Pd(PPh₃)₄ Heck coupling. The remaining one is asymmetric transfer hydrogenation. A-ii, B-i, C-iv, D-iii (a).
Study loop for Organometallic Compounds