Q8 · CSIR NET Chemistry, December 2012
Paper: CSIR NET December 2012 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Oxidative Addition Reductive Elimination · Marks: 2 · Difficulty: Medium
Reactions A and B are, termed as respectively. (A) $\mathrm{SnCl_2}$ + $\mathrm{Co_2(CO)_8}$ $\longrightarrow$ 
(B) $\mathrm{Me_2SnCl_2}$ + 
+ $\mathrm{2NaCl}$
(B) $\mathrm{Me_2SnCl_2}$ + + $\mathrm{2NaCl}$(a)Insertion, Metathesis
(b)Metathesis, insertion
(c)Oxidative, addition, metathesis
(d)Oxidative addition, insertion
Answer
Answer: A ✓ checked by 4AB · confidence high
Explanation
(A) SnCl₂ inserts into the Co–Co bond of Co₂(CO)₈ to give Cl₂Sn[Co(CO)₄]₂ (insertion). (B) Me₂SnCl₂ + 2Na[Re(CO)₅] → Me₂Sn[Re(CO)₅]₂ + 2NaCl is salt metathesis (a).
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