Q87 · CSIR NET Chemistry, December 2012
Paper: CSIR NET December 2012 · Subject: Physical Chemistry · Chapter: Electrochemistry · Topic: Electrochemistry – General · Marks: 2 · Difficulty: Medium
The equilibrium constant for an electrochemical reaction, is
\[ \left[E_{\mathrm{Fe^{3+}/Fe^{2+}}}^{o}=0.75\,\mathrm{V},\ E_{\mathrm{Sn^{4+}/Sn^{2+}}}^{o}=0.15\,\mathrm{V};\ \dfrac{2.303RT}{F}=0.06\,\mathrm{V}\right] \]
(a)$10^{10}$
(b)$10^{20}$
(c)$10^{30}$
(d)$10^{40}$
Answer
Answer: B ✓ checked by 4AB · confidence high
Explanation
E° = 0.75 − 0.15 = 0.60 V, n = 2: log K = 2 × 0.60/0.06 = 20 (b).
Study loop for Electrochemistry