Q59 · CSIR NET Chemistry, December 2014
Paper: CSIR NET December 2014 · Subject: Inorganic Chemistry · Chapter: Main Group Elements · Topic: Main Group Elements – General · Marks: 2 · Difficulty: Easy
The reaction between $\mathrm{SbF}_{5}$ and two equivalents of HF leads to the formation of
(a)$\mathrm{H}_{2} \mathrm{SbF}_{3}+2 \mathrm{F}_{2}$
(b)$\mathrm{HSbF}_{2}+3 \mathrm{F}_{2}$
(c)$\mathrm{SbF}_{3}+\mathrm{H}_{2}+2 \mathrm{F}_{2}$
(d)$[\mathrm{SbF_6}]^{-}[\mathrm{H_2F}]^{+}$
Answer
Answer: D ✓ checked by 4AB · confidence high
Explanation
SbF₅ + 2HF → [H₂F]⁺[SbF₆]⁻ — the superacid 'magic' system.
Study loop for Main Group Elements