Q84 · CSIR NET Chemistry, December 2015
Paper: CSIR NET December 2015 · Subject: Inorganic Chemistry · Chapter: Organometallic Compounds · Topic: Oxidative Addition Reductive Elimination · Marks: 2 · Difficulty: Medium
Heating a sample of $\left[\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Mo}(\mathrm{CO})_{3}\right]_{2}$ results in the formation of $\left[\left(\eta^{5}-\mathrm{C}_{5} \mathrm{H}_{5}\right) \mathrm{Mo}(\mathrm{CO})_{2}\right]$ with elimination of 2 equivalents of CO. The Mo-Mo bond order in this reaction changes from
(a)2 to 3
(b)1 to 2
(c)1 to 3
(d)2 to 4
Answer
Answer: C ✓ checked by 4AB · confidence high
Explanation
Mo–Mo bond order goes from 1 to 3 (c).
Study loop for Organometallic Compounds