Q5 · CSIR NET Chemistry, December 2016
Paper: CSIR NET December 2016 · Subject: Inorganic Chemistry · Chapter: Inorganic Spectroscopy · Topic: Electronic Spectra Tanabe Sugano · Marks: 2 · Difficulty: Medium
The expected number of ${}^{19}\mathrm{F}$ NMR spectral lines, including satellites, for $[\mathrm{XeF_5}]^{-}$ is [Abundance of ${}^{129}\mathrm{Xe}$ $(I = 1/2) = 26\%$]
(a)two
(b)twenty one
(c)three
(d)one
Answer
Answer (as printed): C
Explanation
rx;xH [XeF5]- = = 7 = sp3d3 hybridzation ; Shape = Pentagonal Planar as 74% Xe are NMR inactive hence a singlet of five fluorine and due to 26% nuclei a doublet of satellite. Hence, total number of signal is 3.
Explanation as extracted from the printed page; notation may be imperfect.
Study loop for Inorganic Spectroscopy